Recent content by stupidkid

find the value approximately of 1/1*2+1/2*3+1/3*4... Is there a simple way to find the anwer to problems like this?

its not as easy as that.

sooorry,people if i am dumb, but i aint gettin it, will someone please help me 2 identical buggies each of mass move one after the other without friction with same velocity . A man of mass rides the rear buggy . At a certain moment the man jumps into the front buggy with a velocity...

but there can 1000000000000000s of possibilties for eg 7,6,5,1 or 10,6,3,2 like that

The cards in a set of 36 are numbered 1 to 36. The cards are shuffled and four cards are dealt. What are the chances of them being dealt in descending order? Major help needed I have tried everything in this problem my answer was 1/8 which was wrong I hope you guys can do better.

it is definitely possible and pretty easy but there is no such formula or it maybe be complicated.

Is there a actual way to solve these type of sums! PLS I NEED HELP I AM DUMB.

Solve for x: x^2+x^2/(x+1)^2=3 I got the final equation but I am unable to get the it form there. x^4-x^2+2x^3-6x-3=0

okay so the natural head position causes it then?

EXPLANATION Lets say that the brakes apply a force on the tyres to stop them. NOW due to NEWTONS 3rd LAW there will be a force on the brakes. So by a small quantity the brakes will move, now considering that they don't brake the elastic limit they have to come back to their original position...

you all are saying stuff about natural positions and all blahblahblah but I think the answer lies somewhere in the displacement of the brakes because when this happens the force backward is quite a lot when braking suddenly. That force cannot be due to any natural head position. It is found that...

hey gokul43201, i don't think your answer is right because even if you don't have a seatbelt this happens and the WHOLE car moves backward. did you understand? PS: what's a "typo in the OP.

what? fytbol is talking about the jerk forward not backward. Which is not my question.

hey, danger understood me, that's what I mean, and the relative thing is not what I mean because the car does go backward as seen from an outside inertial frame slightly. And Brewnog the passengers head do move back but because of the force of the brakes not the normal seating position. And...

they are moving forward when the car freezes... how can that help? But I have noticed that the whole car moves backward when the car freezes. That means it is not related to the passengers. I think that when the brakes stop the car the car exert a force on the brakes so they displace and so to...