OOOps, sorry about that.
Well, when work is done on an object, any energy transferred is stored and is calculated by mg \Delta {h}
Work done on an object by, in this case, gravitational force will cause kinetic energy to increase.
Cheers
Ian
Just one more quickie guys please.
I'm calculating the 'Loss of GPE' of this falling stone. I see 'loss of GPE' the same as 'change in GPE', therefore have used the formula: 'delta'GPE= m g 'delta' h where the 'delta' h is the difference in height at 2 different points in time. Is this...
So if it was solid ground, with no deformation, it would all be converted to sound and heat?
So, is gravitational potential energy only 'stored' when the stone is raised again?
Cheers
Ian
Hi. If i drop a stone from a height, i understand its Gravitational Potential Energy will decrease and its kinetic enrgy increases.
Am i correct in saying that when the stone hits the ground and comes to rest, this kinetic energy is now 'stored' potential energy?
Regards
Ian