Recent content by success2be
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Are Two Flip-Flops Sufficient for a Modulo 4 State Machine?
I don't think I'm understanding the requirements correctly. When does Z output 1? It reads as if Z outputs 1 when X & Y are 1, but then why do I need 4 states / 4 modulus?- success2be
- Post #4
- Forum: Electrical Engineering
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Are Two Flip-Flops Sufficient for a Modulo 4 State Machine?
How many flip-flops do I need based on the following requirement? I'm thinking 2 flip-flop since each flip-flop can be a 0 or 1. So each flip-flop holds 2 states. Design a clocked synchronous state machine with two inputs, X and Y, and one output, Z. The output should be 1 if the number of 1...- success2be
- Thread
- Per State
- Replies: 4
- Forum: Electrical Engineering
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Reducing 4 variable algebra in K-map
Thanks to all for validating my results.- success2be
- Post #8
- Forum: Introductory Physics Homework Help
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Reducing 4 variable algebra in K-map
He said looking at my K-map that I can wrap the entire row 2 but can't cancel out C and D. He's reasoning is that they're more than 2 bits apart. Only adjacent cells can be canceled. He then had me draw 7 circles to wrap the 1's in the map. Somehow his analysis ended up with me having 2 XOR...- success2be
- Post #6
- Forum: Introductory Physics Homework Help
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Reducing 4 variable algebra in K-map
If there's 4 inputs to the circuit but one input "C" is not inplemented at all in the circuit, how does the circuit process inputs from "C"? I verified via the truth table that even without the C input the results are still correct. I guess the input for C is not part of the input or output...- success2be
- Post #4
- Forum: Introductory Physics Homework Help
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Reducing 4 variable algebra in K-map
I'm having problems reducing 4 variable boolean algebra in K-map. The equation is: A'B'C'D' + A'B'CD' + A'B + AB'C'D' + AB'CD' Drawing K-map reveil AB\CD 00 01 11 10 00 1 0 0 1 01 1 1 1 1 11 0 0 0 0 10 1 0 0 1 So I wraped entire 2nd row...- success2be
- Thread
- Algebra Variable
- Replies: 8
- Forum: Introductory Physics Homework Help
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Reduce boolean expression to 3 literals
The professor have talked about the K map. The chapter I'm working on have not discussed it officially yet. It'll be the next chapter. I'm wondering if I'll be forced to not use the K map to solve a problem on an exam. Don't know if they only care as long as the solution is correct or that...- success2be
- Post #4
- Forum: Engineering and Comp Sci Homework Help
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Reduce boolean expression to 3 literals
Figured it out. Man this is long. From the second solution A'C' + A (BC + BC' + B'C') A'C' + A (B (C+C') + B'C') A'C' + A ( B + B'C' ) A'C' + A ( (B + B') (B + C') ) A'C' + A ( B + C' ) A'C' + AB + AC' C' (A' + A) + AB C' + AB I wonder is it always a trial and error process in...- success2be
- Post #2
- Forum: Engineering and Comp Sci Homework Help
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Reduce boolean expression to 3 literals
Reduce the following to 3 literals A'C' + ABC + AC' C'(A'+A) + ABC C' + ABC or A'C' + ABC + AC' A'C' + A(BC + C') A'C' + A(BC + C'(B + B')) A'C' + A(BC + BC' + B'C')) I can't go any further. What am I doing wrong? The book has the answer as AB + C'- success2be
- Thread
- Expression
- Replies: 8
- Forum: Engineering and Comp Sci Homework Help