oh, i had them backwards. grr. I guess that would mean that j would be along the x-axis, making that whole thing a bunch of mumble jumble. That should still make the work correct though, as the component in the y-direction will cancel out? I guess that means that the final vector I got was...
Okay, I think that makse sense... let's see if I'm on the right track.
So I figured the magnitude of each vector to be 1800 N/C. The direction of the field produced by the positive charge would then be -1800cos(45)i+1800sin(45)j and the direction of the field produced by the negative charge...
I've tried that a million times and I'm still not coming out with the right answer >:-O By following that procedure, my answer keeps coming out to zero. I got ~1800 N/C for the field of the positive charge and ~-1800 N/C for the field of the negative charge... What am I doing wrong?
I've been working on this problem for awhile now, and I cannot seem to grasp it :cry: .
In this problem, we are to find the strength and direction of the electric field at the point indicated by the black dot (see image below). How would I go about doing this?
Thanks in advance! :biggrin: