Recent content by SuspectX

Oh right, duh... Thanks a lot!

Still confused as to how I incorporate f(x) = f(x+1) I have that between (0 , g(0)) and (1, -g(0)) there has to be a coordinate (x , 0), but then how do I get from that back to f(x) = f(x+1)?

Hm I think that might just complicate things a bit more. I'll try to juggle around with what I had earlier. Thanks, though! Still open to any input!

Wow I'm a bit stuck today. I'm just going around and around in circles with: g(0) = f(0) - f(1) g(1) = f(1) - f(2) I juggle them around and end up with: f(0) - g(0) = g(1) + f(2) f(1) - f(2) = f(1) - f(0) which brings me nowhere.

I've edited my original post to show what I have so far. I can't seem to find a way or simplifying it, so I'm kinda worried I did something wrong...

Homework Statement Find the derivative of: [SIZE="4"]\frac{(x^{3} + 5x^{2} − 9x + 4)^{3/4}}{(x^{4} − x^{3} + x^{2} − x + 1)([x^{5} − x^{-5}]^{1/2})} Homework Equations Product Rule Quotient Rule The Attempt at a Solution I've attempted using the quotient rule for the entire thing...

Homework Statement Suppose that f(x) is a continuous function on [0,2] with f(0) = f(2). Show that there is a value of x in [0,1] such that f(x) = f(x+1). Homework Equations Intermediate Value Theorem? Extreme Value Theorem? Periodicity? The Attempt at a Solution For sure there's an...