Recent content by Svetlana_Vein

Thanks for clarifying Dave.

Homework Statement (x+3)(x-2)/x2-2x Homework EquationsThe Attempt at a Solution (x+3)(x-2)/x(x-2) = (x+3)/x What I don't understand is why I can't simplify this further for instance the x's cancel to give 1: (1+3)/1 = 4/1 = 4 Is it because there is no x next to the 3? Many thanks :)[/B]

Figured it! I didn't realize I had to make the denominators match!

Homework Statement a3/2a5/4 Homework EquationsThe Attempt at a Solution I'm hoping you can help. My solution to this problem would be: a3/2+5/4=a8/6=a4/3 But the answer in the back of my book is given as a11/4 I'm confused!

That is perfect - thank you so much! I didn't even think of that! :)

Hi there, I'm hoping somebody can help me. I have to evaluate the following expression using BIDMAS rules without using a calculator: 1-2/32 I can get as far as 1-2/9 but the answer is 7/9. I don't understand how to get from 1-2/9 to 7/9 in my head. For instance 2/9 = 0.2 recurring, but...

Which distance? Is this from the object to the lens?

Thank you Dale. I think I follow it, and the mathematics don't look too difficult. Apologies in advance if this is a dumb question, but how do I convert the angular resolution into a physical distance? Arcseconds is not something I work with and so I have trouble visualising exactly what it...

That's a fascinating read and a great website thanks. :)

Thanks also to Berkeman, NSASpook and Russ. I'd buy you all a beer if I could! :) Sorry, I was vague on what I meant by resolve. I guess the best answer I could give would be to be able to tell it was a nickel. Now I see that is impossible, but it's what I had in mind. I got thinking about...

Thanks too Dale. I'll check that out when I get home. It's more fascinating than I imagined! :)

Thanks so much D H. That is exactly what I was looking for and the answer is even crazier than I imagined. I really, really appreciate it. One day I want to do calculations like this for myself - but I must learn so much more! Thanks again :)

No, no! I know you weren't calling me an idiot. I just used ignorant because it's a valid word to use when someone (me in this case) has little knowledge in an area. :) Thank you for your answer and I see what you mean about mentioning 'spy satellite'. I should have just said optical...

Maybe the question implies I know more than I do. My initial information was garnered from this video (chapter 8): http://fora.tv/2008/08/11/Richard_Muller_on_Physics_for_Future_Presidents It just got me thinking about the sizes of the optics necessary to resolve a nickel on the ground from a...

It's a hypothetical/theoretical question. I already know the logistics are not good.