Givens for water: m: 0.250kg of water
TW : 95°C
C=4180
Givens for mug: m=0.085kg
TM : 19°
c=107
Required: final temperature of water
Analysis/Solution: Qreleased+Qabsorbed=0, q=mc▲t
mw*cw*Tw + mp*cp*Tp = 0
(0.250)(4180) (T2-95) + (0.085)(107)(t2-19)=0
1045(t2-95) + 9.095(t2-19)=0...
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