Recent content by sww_world

Givens for water: m: 0.250kg of water TW : 95°C C=4180 Givens for mug: m=0.085kg TM : 19° c=107 Required: final temperature of water Analysis/Solution: Qreleased+Qabsorbed=0, q=mc▲t mw*cw*Tw + mp*cp*Tp = 0 (0.250)(4180) (T2-95) + (0.085)(107)(t2-19)=0 1045(t2-95) + 9.095(t2-19)=0...

Hey all, I'm a high school student who has been lurking on here for a while to help with some tougher problems. I'm excited to be on here and am glad to meet you all!