Recent content by SychoScribler

O.K., it looks like I'm on my own for now. \begin{eqnarray}J(x)=\sum_{n=1}^\infty{\frac{1}{n}}\pi(x^{1/n})\end{eqnarray} Let f_1(x)=J(x)=\sum_{n=1}^\infty{\frac{1}{n}}\pi(x^{1/n}). \begin{eqnarray} f_1(x)-\frac{1}{2}f_1(x^{1/2})&=&f_1(x)-\frac{1}{2}f_1(x^{1/2})\\...

That is where equation (1)\hspace{1.5em}J(x)=\pi(x)+\frac{1}{2}\pi(x^{1/2})+\frac{1}{3}\pi(x^{1/3})+\cdots+\frac{1}{n}\pi(x^{1/n})+\cdots is inverted to equation...

Help with Mobius Inversion in "Riemann's Zeta Function" by Edwards (J to Prime Pi) Can someone please add more detail or give references to help explain the lines of math in "Riemann's Zeta Function" by Edwards. At the bottom of page 34 where it says "Very simply this inversion is effected...