Homework Statement
I have the following circuit
http://informatici.vankeer.eu/files/2/Untitled.png
R1 = 22 ohm, R2 = 39, R3 = 82, R4 = 100,R5 = 10
and V = 2volt
I'm asked to calculate the voltage and current over de resistors
when the switch is open and when the switch is closed...
You're correct :)
now I have to calculate the speed after those 3mm and the time it takes to do so
for speed I use v = sqrt(v0+2a(0.003)) but as a is negative it results in a complex number so I just calculated it for -a and then reversed the sign at the end.
Is this a correct approach ...
Well integrating a constant would give a result of the form
E*(0.003)-E*(0) = Vanode-Vcathode
so E then is 2000/0.003 = giving a whopping 6.667e5
and making my electron accelerate at a speed of -1.15e17
Is that even possible ?
Homework Statement
I have given a cathode and a anode being -1000V and 1000V each respectivily
I know the distance between the cathode and anode its 3mm
What I have to do now is calculate the electric field between the cathode and anode and use that to find the acceleration of an electron...