Recent content by Sze Wen

So I can claim that as distance increases, the Wrad must be decreasing. This is because the power density of the antenna will keep on decreasing with the spread of surface area? The surface area is spreading which causes the power that it have to spread out evenly. The Prad should be constant...

Since E is inversely proportional to 1/r, then E at 150m is 3.33 V/m. H = E/377 = 3.33/377 = 0.00883 Am^(-1) (a) Wrad = 0.5(ExH*) = 0.5*(3.33*2)/377= 0.0147 W/m (b) Prad =4*pi*r^2*Wrad= 4156 W Should I assume that the E will stilll be 50V/m at 150m?

At 100m: (a) 0.03315 W/m (b)4166 W Since E is inversely proportional to 1/r^2, then E at 150m is 2.22 V/m. (a) 2.22/377= 0.00654 W/m (b) 4*pi*r^2*Wrad= 1665 W Is this reasoning correct?