Sorry if this aint undergrad its hard to tell what is and what isnt.
I wanted to know if these two things linked or are they completely different? I am looking at the causes of the narrows bridge collapse... it would seem that the flutter has to do with vibrations but not exactly with resonance...
OHH okay I had no idea they could of placed it there! I was looking on the right hand side of this formula sheet for numbers not the left... Okay cool thanks for your help.
Question 1. c) (ii) on this AQA paper... http://filestore.aqa.org.uk/subjects/AQA-PHYA5-1-QP-JUN13.PDF
The solution is here http://filestore.aqa.org.uk/subjects/AQA-PHYA5C-W-MS-JUN13.PDF
So I know that the binding energy will be the mass defect so the value of energy on the left hand side is...
Here I have done the moments on this diagram. This is why I don't get why I need to do P forces. As you can see on this diagram, this is where I am coming from. The moments should be the equation I have given since Fcos and Fsin are negative forces, and 60N works against these forces. I have...
Yeah well it doesn't make sense to me because the bigger force there is, the more likely the block is to slide or topple so... how do I get my actual equation of P and angle after I know the moments? I don't get it.
Okay I see what you mean but that gives me moments about E like these:
Let srt2/25 be c
of P x c = 0.1g x 0.02 --> P = 0.0196/c so... the value of P in this case would be completely independent of angle..?
How am I meant to check if the angle when P = 0.3 is 45 if the value of P is constant...?
I have used phytagoras. the length we looking for is let us say c, c = Sqrt of (0.042 + 0.042)
My calculator said this was Sqrt of 2 over 25.
Also, your second solution, idk what that's about. Dont understand.
Square root of 2 divided by 25?
So now I changed the equation to P = 0.0196/(SQrt(2)/25sinAngle + 0.04cosAngle) but it gives me answer of P = 0.287 for angel= 45 (i) , and 0.36788... for (ii) angle = 15, not the required values of P.
I have attached a copy of the full question and my diagram which I thought was correct but it does not give me the correct answer. The answer for (i) is that it stays put and for (ii) that it topples.
I do not get = 0 for any of them. I get some values... (i) -0.15 for slide, 0.346 for topple...
Thank you for quick response.
So it works similar to the case where (-1)^even = positive and (-2)^odd = negative...
so if n-1 was odd (n was even), then the equation would be unsolvable...
It's an easier solution than I thought... It's nice to know why I turned that expression positive for all...
Hello,
I know that a negative logarithm is undefined.
But I am faced with an equation like this:
-1 x (-2)^(n-1) = -16777216
I divided it by -1 to give (-2)^(n-1) = 16777216
And then took logs to get (n-1) log(-2) = log 16777216
Since I can't work out the log of a negative number, what do I...