Recent content by Tavon

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    Apparent weight of a man standing in an elevator

    Fnet= ma Fnet= 80.0 kg x 0 Fnet = 0
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    Apparent weight of a man standing in an elevator

    0?
  3. T

    Apparent weight of a man standing in an elevator

    Ok. Thankyou. I solved a), b), and c) using the method in the attachment, but I am not sure how to solve d).
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    Apparent weight of a man standing in an elevator

    As gravity increases apparent weight decreases and as normal force increases apparent weight increases?
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    Apparent weight of a man standing in an elevator

    Then normal force has to try harder to push him up, but its magnitude is still lower than the magnitude of gravity.
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    Apparent weight of a man standing in an elevator

    Wait it increases...?
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    Apparent weight of a man standing in an elevator

    It stays the same.
  8. T

    Apparent weight of a man standing in an elevator

    Fg and Normal Force but if the elevator is accelerating down the man's apparent weight will decrease.
  9. T

    Apparent weight of a man standing in an elevator

    Force applied as well or Tension since the cables lower it?
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    Apparent weight of a man standing in an elevator

    2? Normal Force and Fg?
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    Apparent weight of a man standing in an elevator

    I don't think so. It doesn't say so in the question so I guess it still applies force on the elevator.
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    Apparent weight of a man standing in an elevator

    That's what I thought at first but the answer in my Physics 20 workbook said 785 N and I tried the method mentioned earlier to get the answer but I didn't understand how it worked. I thought it might be 785 N since gravity is 9.81 and it is still acting on the elevator even though it isn't moving.
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    Apparent weight of a man standing in an elevator

    Homework Statement An 80.0 kg man is standing on a scale calibrated in Newtons inside an elevator. Determine the apparent weight of the man as shown by the scale as the elevator is a. stationary. [ans.785 N] b. accelerating downwards at a rate of 1.10 m/s^2. [ans. 697 N] c. accelerating...
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