Ok, let me explain. The textbook has no mention of l'hopital's rule, thus we cannot use it. The way we are supposed to solve limits is by the "theorem" : the lim as x approaches 0 of sin(a*x) / sin(b*x) = a / b. To solve trigonometric limits, we use trigonometric identities usually to reach a...
So I've been trying to solve this limit problem for some time. Here is the problem:-
\lim_{x\rightarrow 0} {\frac{6sin(x) - 2sin(3x)}{tan^3(3x)}}
I cannot use l'hopital's rule to solve it. I've tried taking 2 as a factor, then trying to use a trig identity, but I couldn't figure a...