I can't get to construct two good functions now, but
take, f(x)= -1/x - 2 and construct g(x)= atan(bx) + c where a, b and c such that g(-1/2)=0 and blows up at g(0).
Strictly in (-1/2,0), f(-1/2) = g(-1/2) and as x -> 0 f,g -> infinity
I don't know if in this case f>g, but as x -> 0 either f...