W=Fd
=200*300
=60000
60000=½*1000*v2-½*1000*252
=500v2-312500
372500 = 500v2
v2=745
v=27.3
Yea see for yourself, its a multiple choice question. And I changed the original post so it makes some sense.
Homework Statement
A 1000kg car is moving at 25ms when a net force of 200N acts to slow the car. This force acts while the car moves through a distance of 300m. Find the new speed.
Homework Equations
Kinetic Energy equation
v2=u2+2as
The Attempt at a Solution
Attempted the use of Kinetic...
Alright -2.59×105 is the answer I got, the problem was that I was doing 502/3.6 instead of (50/3.6)2.
Thanks for the help, feeling extremely stupid. :mad:
The question is from a paper which does not require the use of constant acceleration equations. It would seem bizarre to use a formula that hasn't been introduced to us yet.
Also, the solution is written as -2.59*10^5 Joules in the paper.
Homework Statement
The law of conservation of energy applies to the motion of vehicles. Find the work done on a 1200kg vehicle when it slows from 90kmh-1 to 50kmh-1 in 8.0 seconds.
Homework Equations
W=1/2mv^2 - 1/2mu^2
The Attempt at a Solution
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W=0.5*1200*50^2 - 0.5*1200*50^2