Recent content by TDizzl

The answer is correct as ms-1

Thanks, I managed to get the answer, all I done was 27.5-25=2.5 25-2.5=22.5

W=Fd =200*300 =60000 60000=½*1000*v2-½*1000*252 =500v2-312500 372500 = 500v2 v2=745 v=27.3 Yea see for yourself, its a multiple choice question. And I changed the original post so it makes some sense.

Homework Statement A 1000kg car is moving at 25ms when a net force of 200N acts to slow the car. This force acts while the car moves through a distance of 300m. Find the new speed. Homework Equations Kinetic Energy equation v2=u2+2as The Attempt at a Solution Attempted the use of Kinetic...

Alright -2.59×105 is the answer I got, the problem was that I was doing 502/3.6 instead of (50/3.6)2. Thanks for the help, feeling extremely stupid. :mad:

So how do I get the answer as -2.59×105?

Yea its like -3360000J, that's what I got

m=1200kg v=50kmh-1 u=90kmh-1

No, that was how I substituted the values in as an attempt to answer the question.

The question is from a paper which does not require the use of constant acceleration equations. It would seem bizarre to use a formula that hasn't been introduced to us yet. Also, the solution is written as -2.59*10^5 Joules in the paper.

Yes, my bad Its W=0.5*1200*50^2 - 0.5*1200*90^2

Homework Statement The law of conservation of energy applies to the motion of vehicles. Find the work done on a 1200kg vehicle when it slows from 90kmh-1 to 50kmh-1 in 8.0 seconds. Homework Equations W=1/2mv^2 - 1/2mu^2 The Attempt at a Solution [/B] W=0.5*1200*50^2 - 0.5*1200*50^2