Recent content by teddy1975

okay, so here's another question: the reaction for G-3-P oxidizing to 1,3-BPG is: G-3-P + NAD+ + Pi --> 1,3-BPG + NADH + H+. I understand that the hydride ion leaves G-3-P and donates two electrons and one proton, which neutralizes the charge on NAD+ and gives NADH. But it is only giving one...