Recent content by terry

Thats what I got...albeit not so easily. *sigh*...I guess the question was wrong. Thanks for the help

Yeah, sorry inelastic collision. Has anyone seen a general form for m3/u3? I was asked to show that {m_3}^2=m_1^2+m_2^2+2m_1m_2(1-u_1u_1)u_3=\frac{m_1 \gamma_1 u_1 + m_2 \gamma_2 u_2}{m_1 \gamma_1 + m_2 \gamma_2} Its the expression for m3 that bugs me. I tried picking m1,m2,u1,u2, then using...

Say we have 2 particles moving in the same direction, which undergo an elastic collision. Take the rest mass of particle to be m_1, the rest mass of particle 2 to be m_2, with velocities u_1,u_2, with u_1>u_2. Assume they collidie inelastically to form a new particle m3 Are my conservation...