Recent content by Texhno

Can you check if I did these problems right? Questions are on this site: http://home.earthlink.net/~suburban-xrisis/pics01.jpg 84) PE=mgh 85) PE=KE mgh=.5mv^2 gh=.5v^2 v=sqrt(2gh) 86) PE=mgh PE=.5kx^2 mgh=.5k(-y)^2 87) 0.5kx^2=.5mv^2 k=(mv^2)/(x^2) k=(mv^2)/(y^2)

Use the equation T=2*pi*sqrt(m/k) and solve for k. Get that and sub in what you got for k into PE=.5kx^2 PE=(4*pi^2*m*x^2)/(2*T^2)

if this ball with a velocity of sqrt(gh+v^2) on the top of the hill rolls down that hill and rolls to a flat surface. How much force is required to stop the ball in "d" meters? I know that F=ma but there is no exceleration so what is the force required?

Then I'm correct...I said "so if the block of wood went over a hill that was half the height of an original hill, then the velocity would double because not all of the KE is turned into PE. Since there is access KE, the velocity would increase by half." I think I meant to say "the velocity would...

saying that mg(.5h)=.5m(.5*v^2) since the height is cut in half, then the KE is also cut in half?

Even though the block would gain velocity down a hill and have more velocity to attack the second hill that has half the height, the velocity is actually half the original because the hill is half the original height?

so if the block of wood went over a hill that was half the height of an original hill, then the velocity would double because not all of the KE is turned into PE. Since there is access KE, the velocity would increase by half. am I correct?

If a block of wood is placed on a hilly frictionless track, would the velocity stay constant at the top of each hill if the height of each hill was the same? Since as the block of wood slides down a hill, it gains kenetic energy looses potential energy, but as it rises up the hill, the PE...