Vela. Thank you so much! I started to realize that the soft drink is not a constant temperature reservoir.
However, that arouses my another question about entropy (ds = δQ/T). I now realized that I don't really understand this equation at all.
In this questions, why do they plug in T = 293.15 K...
But I still don't understand what I am doing wrong exactly in this problem?
I think I did calculated the carnot efficiency β and used the heat capacity to calculate ΔU. Finally, I found QL. By using the β and QL, I computed the work. But it still does not match the correct answer. I don't know why.
Homework Statement
The temperature of a 12-oz (0.354-L) can of soft drink is reduced from 20 to 5 ºC by a refrigeration cycle. The cycle receives energy by heat transfer from the soft drink and discharges energy by heat transfer at 20 ºC to the surroundings. There are no other heat transfers...