Recent content by thata6

find the speed of an electron. given that the momentum of the electron is 4.8 x 10-19kg.m/s p=mv/ sqr root of 1-(v/c)2 use the above equation to find v. The solution in the textbook re-writes the above equation as p=(mc)(v/c)/sqr root 1-(v/c)2. How on Earth do they come to this...

hi there. ok let me step you through my thinking 1.the energy of the photon will be the energy of the positron plus the energy of the electron energy of e- = rest energy + kinetic energy = Mc2 + 3.52x10-14 (220 Kev) = 8.1791x10-14J...

hi there. ok let me step you through my thinking 1.the energy of the photon will be the energy of the positron plus the energy of the electron energy of e- = rest energy + kinetic energy = Mc2 + 3.52x10-14 (220 Kev) = 8.1791x10-14J...

never mind I solved this using total E = rest E + KE E = Mc2 + 220Kev double this since we have e- and e+ and you have the protons E then use E=hf to find wavelength.

an electron-positron pair, each with a kinetic energy of 220 Kev, is produced by a photon. find the energy and wavelength of the photon. started with E=hf=pc , and the fact that p=mv, but his not working