Recent content by thebe39

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    Electrostatics: Two charged balls with attraction

    So I'm going to let r^2 equal each other kq1q2/F = k(q1 +q2)^2/F(4) So I isolate for q2 right? or do I say that kq1q2/F = k(q1 +q2 divide by 2)^2/F(4)
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    Electrostatics: Two charged balls with attraction

    btw the answer to this problem is apparently a) -5x10-6 C b) 0.10m But I really just want to understand what I'm doing with the steps.
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    Electrostatics: Two charged balls with attraction

    how did you get F=Kq(q1+q2)/(4*r^2) ? where does the extra q come from?
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    Electrostatics: Two charged balls with attraction

    well I know that in the beginning the q2 should have a - charge since it is attracted to the q1 and then after the wire it should become -. I'm not really sure how to isolate for q2 from the equation.
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    Electrostatics: Two charged balls with attraction

    Hi, I have an exam coming up soon. But I thought I would clear my doubts ahead of time. 1. A fixed conducting ball has charge q1= 3X10^-6C. An identical ball with charge q2 is held at a distance x away from q1. The two balls attract each other with a force of 13.5N. The balls are then...
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