Recent content by thebe39
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Electrostatics: Two charged balls with attraction
So I'm going to let r^2 equal each other kq1q2/F = k(q1 +q2)^2/F(4) So I isolate for q2 right? or do I say that kq1q2/F = k(q1 +q2 divide by 2)^2/F(4)- thebe39
- Post #8
- Forum: Introductory Physics Homework Help
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Electrostatics: Two charged balls with attraction
btw the answer to this problem is apparently a) -5x10-6 C b) 0.10m But I really just want to understand what I'm doing with the steps.- thebe39
- Post #6
- Forum: Introductory Physics Homework Help
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Electrostatics: Two charged balls with attraction
how did you get F=Kq(q1+q2)/(4*r^2) ? where does the extra q come from?- thebe39
- Post #5
- Forum: Introductory Physics Homework Help
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Electrostatics: Two charged balls with attraction
well I know that in the beginning the q2 should have a - charge since it is attracted to the q1 and then after the wire it should become -. I'm not really sure how to isolate for q2 from the equation.- thebe39
- Post #3
- Forum: Introductory Physics Homework Help
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Electrostatics: Two charged balls with attraction
Hi, I have an exam coming up soon. But I thought I would clear my doubts ahead of time. 1. A fixed conducting ball has charge q1= 3X10^-6C. An identical ball with charge q2 is held at a distance x away from q1. The two balls attract each other with a force of 13.5N. The balls are then...- thebe39
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- Attraction Balls Charged Electrostatics
- Replies: 8
- Forum: Introductory Physics Homework Help