You are very right Russ pressure is a value of, Newtons divided by Meters squared. N/Msquared
I am trying to figure out how many square meters are at the base of a nano tube. Perhaps you could enlighten us.
OK thank you for all the consrtuctive results of this thread.
New thread just not officially started yet.
Given the formula rho*g*h
A tube extending to space with a small diameter. What possible "not practical" applications could there be to launching a satellite into space using the...
actually he is saying that it is a full tank and a few drops are added to fill the column otherwise why make the column so high.
So stated again could only a few drops of water ACTUALLY increase the pressure by such a massive amount or is the formula perhaps flawed in applications of this...
http://www.ac.wwu.edu/~vawter/PhysicsNet/Topics/Pressure/HydroStatic.html
Go to this part it is a near match for the image described in the original question
Vessel C: Again we could divide the water into three sections. The middle section is similar to that of vessel A or B. Since the...
You are correct the formula will give the pressure at the BOTTOM of a column of water even if that BOTTOM is not at the BOTTOM of the tank itself.
There still seems to be no one that has stated a formula to say what the presssure is at the side of a tank or pipe and in what way the nano tube...
The pressure P is the same on the bottom of each vessel.
Why the pressure does not depend upon the shape of the vessel or the amount of fluid in the vessel rests upon three things:
a. Pressure is force per unit area and this is not same as the total weight of the liquid in a vessel.
b...
OK i do understand why you are using the rho*g*h
However what method would you use to determine the wall thickness of a tank of water or the wall thickness of a water pipe.
Or would their be no pressure pushing the water out of the sides.
Could you use a pipe with a wall thickness of 1...
Ya russ i am aware of that formula perhaps you misunderstood the statement i made.
I use that formula for each column then apply an average to find the new pressure from the old supposedly know pressure.
The single small tube of great height would not pruduce a massive amount of overall...
Given most other factors as assumed irrelevant for this application.
It would be prudent to take the the column of water for that chimney as a single column of many columns with in the whole tank.
You would then take the the area of that chimney column and find how many others of that same...