Recent content by TheJfactors

Here's a slightly easier to read version, I didn't see the formatting errors when I copied it over from equation editor: (((1+\frac{1}{4})+\frac{(\frac{pi}{2}-t)+m}{pi})∙(1+m' )+((3-\frac{1}{4})-\frac{(\frac{pi}{2}-t)-n}{pi})∙(1-n' )) + (((1+\frac{1}{4})+\frac{t+m}{pi})∙(1+m'...

I can't seem to find an explicit or analytical solution to a boundary value problem and thought I might ask those more knowledgeable on the subject than me. If t is an independent variable and m(t) and n(t) are two dependent variables with the following 8 constraints: a) m' =0 @T=0 and...

Can we calculate self inductance from this by anychance? I am under the impression if the E field exists pointing in the opposite direction of the current and a high rate of current change produces a proportionally larger E field then this E field must oppose movement of charges such that there...

I think equation 24 and 25 are for a current impulse function, I believe 10 and 11 are for the ramp function. Equations 24 and 25 seem to make sense because the E and B field decay as a function of time as one would expect. From equation 10 and 11 it seems that the E field grows in strength as a...

So I guess now some clarifying questions arise. Namely if u= c*t/s in the previous links i posted where s is the distance from the z axis, does the E field continue to increase with time as long as K (the current ramp rate) is the same? Also what happens in discrete cases when the current goes...

After much searching I think I may have finally found the answer: http://lief.if.ufrgs.br/~ambusher/griffiths/PS10s.pdf I believe Problem 5 (or Griffiths Problem 10.9) is almost exactly the same setup that we are currently running. The results are rather interesting. Here's the problem...

Are you certain about Ir=k(t−d/c) ? I feel like it should be Ir=k⋅t−d/c otherwise the delay scales with the current ramp rate which doesn't have to do anything with the position it is being sampled from? Idk, this is far from my forte haha. Not entirely sure how to actually evaluate the triple...

Ok I'm going to do a lot of reading cause it is clear to me that I have a lot to learn haha, I will let you know if I find anything strange or different from what you posted. But in the mean time if the B-field is as you have written it, are you plugging that back into the equation you worked...

I appreciate your efforts, any new direction you think might be worth taking? The Faraday's law approach still exists but there needs to be a few boundary conditions if the differential equation is to be solved.

Interesting method, didn't expect to use polarization current. So the answer is zero? Because if you multiply the magnetic field by r there is no longer an r component in the equation Bϕ=μ0(I0+kt)/(2π) , and the derivative with respect to r is just zero then? Or I may just be a bit rusty on my...

I am looking for the electric field outside of the wire, not the emf inside of the wire. If current is changing ∂I/∂t ≠ 0 then there is a changing magnetic field outside the wire that must produce some non electrostatic electric field outside of the wire also. Let me restate the question using...

Yeah I still end up with basically the same problem/ a PDE I can't solve, I need boundary conditions to solve for the result of Faraday's law in cylindrical coordinates (can't use polar coordinates in 3D correct?) or Cartesian coordinates as I originally did in the beginning. This is the result...

Also I thought I'd mention that it may be impossible to have current flowing in an infinitely long wire and a short straight wire may be the only possible scenario to solve for. Either way I am just trying to consider a magnetic field circling only in the X and Y directions, where Z axis points...

I see a lot of problems on constant current inducing a current in another wire due to its associated magnetic field, but not so much a single wire's induced electric field. If the current along an infinitely long wire is flowing out of the page and inducing a counter-clockwise spinning magnetic...