Ah, I read your previous post wrong, my fault... it would be 12.5.
But would 52.5 still be the end point, right, since you can't extend the graph to t = 10?
I've gotten everything except the last problem;
3) Calculate the magnitude of the car’s average velocity from 5 s to 9 s.
Answer in units of m/s.
Here's my work so far:
5 to 6: v = 13, x = 21.5
6 to 8: v = 11, x = 45.5
8 to 9: v = 3, x = 52.5
You said the average velocity is total...
Hi gneill,
So for 1), here's my work:
0 to 1: x - 0 = 0(1) + .5(0)(1)^2 = 0
1 to 3: x - 0 = 0(2) + .5(2)(2)^2 = 4
3 to 4: x - 4 = 4(1) + .5(1)(1)^2 = 8.5
4 to 5: x - 8.5 = 4(1) + .5(1)(1)^2 = 13
Would 13 be the correct answer, or am I missing anything?
Homework Statement
Consider the acceleration of a particle along a straight line with an initial position of 0 m and an initial velocity of 0 m/s.
1) Calculate the magnitude of the displacement after the car travels the first 5 s.
Answer in units of m.
2) How far does the car...
Thanks for the help...now for finding the position at 5s, the second part of the problem I listed above, I used this equation:
x-x0 = v0t + .5(a)(t)^2
For 0 to 2 seconds my equation was: x-(-15) = -3(2) + .5(7)(2)^2 = -7
Then for 2 to 5 seconds, this was my equation: x-(-7) = 14(3) +...
I'm adding the velocities because it isn't constant over the entire time, but it is constant at different intervals, so to find the velocity at a given time, I would add all the constant velocities up to that given point, right? If not, what would I do?
Homework Statement
Consider the plot below describing the acceleration of a particle along a straight line with an initial position of −15 m and an initial velocity of −3 m/s.
A) What is the velocity at 5 s? Answer in units of m/s.
B) What is the position at 5 s? Answer in units of...