Then using a vector representation of the derivative definition, Δz is a vector that approaches zero to find the limit of the function. What if z=x+iy is viewed as a point rather than a vector?
I'm curious how the derivative of a complex function can be represented visually. It is defined as the limit of (f(z_{0} + Δz) - f(z_{0}) / Δz as Δz approaches 0. Is it right to say that f(z_{0} + Δz) represents a neighborhood of radius Δz around z_{0} in this case? Does the derivative still...