Recent content by thercias

Homework Statement What will the pH be by adding 1M HCL and 1M NaOH to pure water? Homework Equations pH= -log[H+] The Attempt at a Solution Well, If we form the reaction formula we get HCl + NaOH ---> H20 + NaCl This is a neutralizing reaction, so the net effect produces just water...

Homework Statement A parity bit will be 0 if the data contains an even number of 1’s and it will be 1 if the data contains an odd number of 1’s. If during transmission a 1 is changed to a 0 or vice versa, then the parity check at the receiver will fail. Determine the parity P for 4–bits of...

Okay got it I think. I was getting jumbled up with the original question when writing down my answers. Vout = -VinR2/R1 in that case I think. Thanks for the explanations, and have a good night's sleep. Like you pointed out, I would appreciate if someone would chime in and verify if these...

Unfortunately, I'm not really understanding. So if my answers for part A) and B) are right, I don't understand what is going wrong with part C). Current through R1 = Vin/R1. Voltage drop across R2 = IR2. Therefore the voltage drop across R2 = Vin*R2/R1 I also thought, applying kirchhoffs rule...

Voltage drop across R2 = IR2 = VinR2/R1 So Vout would be = Vout/2 + VinR2/R1 Vout =2VinR2/R1 ? I just saw your question Is the input bias current difference through the current from the + and - inputs? As for explaining ground, I think this example is kind of hard to understand since the R1s...

Current is flowing through R1 and R2. But they are separated by a junction. So would I = Vin/R1 = Vout/R2 ? And V(out) = V(-) + IR2? edit: I wouldn't be Vout/R2, it would be V2/R2

It would be an inverting amplifier. So, the most difficult part for me in understanding these circuits is coming up with an expression for V+ or V-. For some reason I'm just not grasping some fundamental concept,no matter how hard I try and research. If R1 is grounded, how would that affect V+...

Ok so I redid that bit. So we have V(-) = Vout/2 Using kirchhoffs law, the current through the R1 would be Vin - IR1 - Vout/2 = 0 therefore, I = (Vin - 0.5Vout)/R1 and Vout would be -Vout/2 - IR2 = Vout Vout = IR2/1.5 =-R2(Vin-0.5Vout)/1.5R1 Would this be correct? I'm kind of confused...

Homework Statement Consider the circuit drawn below This diagram was the closest I could find online to the one equivalent to my question, but there are some adjustments I need to clarify. 1)Replace Rz, Rf, and Rin, to R1. 2)Also, in my question, there's an extra wire connecting Vout to the...

Ok, so I googled it. the van't hoff factor of glucose is 1. the van't hoff factor of nacl is 2. does this mean glucose will have half the concentration as nacl? edit: osmotic pressure = (van hoff factor) * c * Boltzmann constant * temperature for glucose, if the van't hoff factor is half of...

yes, they are talking about sodium chloride. And what do you mean about the correct formula? I'm using Osmotic pressure = concentration(number density of solute molecules) * Boltzmann constant * temperature. What formula am i supposed to use?

Homework Statement t[/B] You are trying to make artifiial blood cells. You have managed to get pure lipid bilayers to form spherical bags of radius 10um, filled with hemoglobin. The first time you did this, you transferred the "cells" into pure water and they promptly burst, spilling the...

Homework Statement A system has three energy levels, E1=0, E2 =1 and E3 = 2. In a certain state of the system, the probability that energy level 1 is occupied is 0.1, that energy level 2 is occupied is 0.8, and that energy level 3 is occupied is 0.1. Is this an equilibrium or a non-equilibrium...

Homework Statement A solid sphere of radius R has a spherical cap, defined by the cone theta = alpha, removed from its "north pole". Determine the volume of the sphere without cap. Homework Equations The Attempt at a Solution Well obviously, the volume would be volume of sphere -...

Wow, that was very clear. Thanks for the amazing explanation. I definitely have a better understanding of the surface integrals now, and it looks like I was doing my line integrals right after all.