Recent content by Thermofox

Okay, I was able to finish the problem. Thanks for the help!

This. That's the mistake, I treated ##L\space atm## as ##J## When I did ##W_{AB}= -P_{AB} (V_B - V_A)= -20atm(10-5)L\neq -100J##, but ##-100 atm\space L=101,325J(-100)\approx -10,132J## Now ##\Delta U_{AB} = Q + W= 25,304J -10,132J = 15,172J##. If I compare it with ##\Delta U= nc_v\Delta...

I think I know how to solve the problem, but I've incurred into some problems with my computations. Let's take for example the first question, in the monoatomic case. The total heat absorbed by the gas coincides with the heat absorbed during ##A\rightarrow B##. Since the pressure is constant...

Wonderful, thanks again!

##E_i=E_f \Rightarrow mgh= \frac 1 2 mv_{y,\text{right before collision}}^2##. Therefore ## v_{y,bc}= \sqrt{2gh}##. ##E_{\text{right after collision}} = E_f \Rightarrow \frac 1 2 m(0.8v_y)^2 = mgh_1## ##\Rightarrow h_1= \frac {\frac 1 2 (0.8v_y)^2} g## I never considered that you can do an...

That's great to hear. Thanks for your immense patience!!

##\begin{cases} N_y=mg+f_y \\ N_x + f_x = ma_c \\ f=\mu_s N \end{cases}## ; ##\begin{cases} N \frac {\sqrt{3}} 2=mg+ \frac f 2 \\ \frac N 2+ f\frac {\sqrt{3}} 2 = ma_{c,max} \\ f=\mu_s N \end{cases}## ##\Rightarrow N \frac {\sqrt{3}} 2 - N \frac {\mu_s } 2 =mg## ##\Rightarrow N= \frac...

Yes, because ##f_{s,max}=N\mu_s##

Yes, I just had taken it for granted. I should've written ##y(t_1)##, because I had defined ##t_1## as how you defined ##t_c##

You just made me realize that, thanks.

Because friction can no longer hold the block still.

I wrote ##-h= -\frac 1 2 gt_1^2## because ##y(t)=0## and ##y_0=h##

oops! A ##t## jumped away. It should be ##y(t)= y_0 + v_{0,y} t + \frac 1 2 a_y t^2## ##h## would then be negative, I didn't consider that the positive direction is determined by the y-axis. To do the second point I need to find ##h_1##. For this I need to use ##h_1=y(t_1)= y_0+v_{y,after...

The block starts moving.

I conceptually know how to solve this problem, what I struggle with is the direction of the acceleration. For example to solve the first question I need to find the horizontal displacement when the ball hits the ground. Therefore ##l_0= x(t_1)= x_0 + v_0 t_1##, where ##t_1## is the moment the...