Complement (90), Supplement (180)...I knew what you meant!
So, when we use the Law of Sines to get the other angle, we get 15.49
(sin 75 * 60) / 217 = .267
arc sin (.267) = 15.49
205 - 15.49 = 189.51
Or is there a better way to do that? That still doesn't seem right.
Awesome, thank you! I didn't even think of the complement!
Now,
(sin 75)/(217) = (sin A) / 225
(sin 75) * (225) / 217 (which is actually 217.34) = .999966
arcsin (.999966) = 89.53
When I use the arctan in my first method, I knew to add 180 because both my y and x were negative...
I'm so sorry for being difficult :blushing:
360 - 205 = 155
180 - 100 = 80
155 - 80 = 75
I think I figured out how to do the head-to-tail addition. But the actual addition of the bearings (205 and 100) is still confusing me as to how to get 75. I'm baffled :confused:
I'm just not...
I have no idea why I made it seem like I needed all of the angles to use the Law of Sines; that was stupid of me.
I still don't see where you were able to come up with the 75 degree angle from the addition of a 205 degree bearing and a 100 degree bearing.
I guess I didn't phrase my question correctly. I'm just unable to see where the addition of a 205 degree bearing with a 100 degree bearing gives you 75 degree angle to use.
I'm just having a lot of trouble visualizing the addition of the vectors on a diagram, and then seeing the angles they...
Forgive me for being dense, but how would head-to-tail work in this instance? Would you take the non-arrow end of the 100 degree bearing and place it on the arrow end of the 205 degree bearing? But even then, how would that give you 75?
From there, you would still need at least one more...
Still getting acclimated to the whole thing, thank you for your patience!
I don't understand where you are getting 85 from.
But if I were to use 85, it would be something like:
c2=2252 + 602 - (2)(225)(60)(cos(85)
c2 = 51871.75
c = sqrt (51871.75) = 227 (** the answer is 217)
And now because...
Homework Statement
An airplane is traveling with airspeed of 225 mph at a bearing of 205 degrees. A 60 mph is blowing with a bearing of 100 degrees. What is the resultant ground speed and direction of the plane?
Homework Equations
x = u cos(degrees)
y = v sin(degrees)
However, I think the...