thanks for your replies :)
I was thinking about this problem earlier today and I came up with this:
my initial vertical velocity = sin(20) (times) 50m/s = 17.101m/s
my horizontal velocity = cos(20) (times) 50m/s = 46.98m/s
I know that my horizontal is
d=vt (or in terms of t: t = d/v)
so: t =...
I hope it is ok that I'm bumping this topic back up:rolleyes:
I'm having issues with the same problem:
I drew/scanned an image:
http://img150.imageshack.us/img150/6829/scannp3.jpg
So what I have gotten is this:
d = starting d + initial v•t + 1/2•a•t(squared)
I made my starting...