Recent content by thomas91

Thanks for everything Orodruin! Have a nice day :D

It will be ? Simplified: Thanks!

Finally! How can I calculate the oscillation period of the bean?

Hello! ¿ ? Thanks!

Then... Recapitulating 2nd condition = > θ' = 0 and t = 0 (rest position) So I obtained B setting θ' (t = 0) = 0; so B = 0 And now, knowing A and B I have the solution for cos(θ/2)

Then... Is correct? Thanks!

Sorry but... If I know and I know B = 0. What I need to get?

Does the rest position mean that the velocity mean that θ' = 0 for t=0? I tried to derivate θ and solve B for t=0 and I obtain B=0...

Can I set two arbitrary (Between 0 to 2π ) differentes values of θ and solve a equation system for t and B?

Hello! I can't find the other condition. Can you give me a clue? Thanks

But ... B is out of the equation because sin (0) = 0 Then B may be any value. Yes? Thanks!

Hello! I think this: a) Find the solution θ(t) which in the case of a bead at t = 0 falls from rest from the corresponding point θ= π/2 Then: What do you think?

Edit: The equation is homogeneous. No particular solution. But then we can not replace, I can not find the solution

Sorry! It was a mistake... The linear equation is: The characteristics polynomial is: With complex roots: The general solution: We need to know the particular solution. True?Thanks!

Hello! If you do not mind, I prefer to finish the exercise by this method and later solve by the method you suggest Then, the second derivative is: Replacing first and second derivative: And simplifying: Simplifying again: What do you think? Thanks and have a nice sunday