Thanks for the explanation. However when I plug in the figures into the formula, I come out with 10KW
P(w) = {\frac{τ(nm)~x~ 2π ~x~ω(rpm)}{60}}
I then plug my figures in:
P(w) = {\frac{47(nm)~x~ 2π ~x~2200(rpm)}{60}}
I get 10,828w.
where have I gone wrong?
Thanks
Hi Russ, thanks for your reply.
It is an average car, the voltage 12v and the current is 150A max. For reference the datasheet I found was here
I took a look at the wiki page but I'm a little confused as to what I am looking for - I'm not sure what to apply to which formula :confused...
Hi,
I'm looking around for a replacement alternator and came across the specs which state max current available at 6000rpm and requires 47nm of torque.
I was quite suprised with this needing that amount of torque. So I'm starting to imagine a typical diesel which most don't get up to...