Recent content by thomasrules

Homework Statement A woman lives on an island 2km from the mainland. Her fitness club is 4km along the shore from the point closest to the island. To get to the fitness club, she paddles her kayak at 2km/h. Once she reaches the shore she jogs at 4km/h. Determine where she should land to reach...

Homework Statement Mike, who i standing on the deck of a yacth that is traveling due west at 6km/h, sees a sailboat sailing southwestat 4km/h, 3km northwest of the yacht. How close to each other do these boats get?Homework Equations The Attempt at a Solution My drawing is: |...

CAN SOMEONE PLEASE HELP ME UNDERSTAND THIS PARAGRAPH. I THINK HE HAS THE WRONG DRAWING, SET UP

So what exaactly do I do with the first paragraph? And the second paragraph isn't it suppost to be V=(0.4+0.4+2x)h\frac{1}{2}(2.5) ?

Yea I got it thanks Halls of Ivy... I get to stay in school :D

OMG YOU ARE CORRECT! Thanks man. I'm slow. What's your paypal how much do I owe you. :-p And now I have another similar one I'm struggling with it :S

NO! but we only have found the time man not the distance

The ships get 0.707km to each other btw thanks for all your help so far

I got it to be: After the expansion and derivative dD/dt=200t-98.84/(the rest here doesn't matter cause I'm setting other side to zero)

D^2=(-3.53+6t-0)^2+(3.53-8t)^2 I did derivative. Set it to 0. Got 0.7 Thats not the answer I'm suppost to plug time into the D^2 and get the distance correct?

**** or is it A(8t,0) B(3.53,-3.53+6t) My guess is that's right if not I quit school

ah crap... A is (8t,0)

A's position at t=0 is (0,0) A's position as a function of time is (3.53-8t,0) B's position as a function of time is (3.53,-3.53-6t)

yes those are the coordinates.from the origin (0,0) using pythagorean theorem, i use 5sin45=a=3.53, b=3.53

yes I have a drawing. I used the sin law to find the distance of the 2 sides. Coordinates (3.53,0) and (3.53,-3.53) By the way how do you put spaces in latex coding I tried \\ it didnt work