Recent content by thua

Homework Statement I've calculated the time, the distance, the height of the counterweight before launch, the mass/weight, and I need to calculate the energy efficiency. How to go about it? h = 0.71 m m = 1.445 kg g = 9.8 m/s^2 t = 0.7 s x = 4.44 m Homework Equations Eg = mgh Vix = x/t y =...

i think i got it now... thanks a bunch!

Students from a history class prepare a trip that will cost them a total of $189 that will be shared between them. The day before the trip, 6 students discovered that they can't participate in the trip. To avoid cancellation, the rest of the class decided to pay an additional $2 each. How many...

does that mean that the answer is wrong again? because i came up with 16000 N which is 1.6 x 10^4 and they say its 1.6 x 10^3 kg. and does 1 N equal to 1 kg... I am not very familiar with that. but 1 N actually equals to 1 kg x m/s^2, though right?

okay thankssss... and for number 2... i really don't know how itll work cause mass is equal to net force over acceleration, but all i have is net force... no acceleration... so how would that work out?

that still doesn't work though because the net force comes up to -8670 N [S]. i think I'm totally missing out on something here...

whozum... is that to find the acceleration? (22 m/s [S])^2 = (0 m/s [S])^2 + 2a(330 m) a = 0.73 m/s^2 [S] f = ma f = 8760 N [S] <----- something's still wrong

1. A 1.2 x 10^4 kg truck is traveling south at 22 m/s. a) What net force is required to bring the truck to a stop in 330 m? b) What is the cause of this net force? Answer: a) 8.0 x 10^3 N [N] 2. Each of the four wheels of a car pushes on the road with a force of 4.0 x 10^3 N [down]. The driving...

When the Crampton coal-fired train engine was built in 1852, its mass was 48.3 t (1.0 t = 1.0 x 10^3 kg) and its force capability was rated at 22.4 kN. Assuming it was pulling train cars whose total mass doubled its own mass and the total friction on the engine and cars was 10.1 kN, what was the...