Recent content by thunderbird

Ok like this?: e1 = k1 - k2 + k3 e2 = 2 k1 + 0 k2 + k3 e3 = 0 1 0 Now what? I think I need to understand what's going on, not just what I need to do...

I looked but it doesn't really say. We don't have a textbook for this actually and the notes are very vague. This is what it says: We can write x(0) = c1 k1 + c2 k2 + c3 k3 + c4 k4 (6.2) for some coefficients c1 , c2 , c3 and c4 uniquely determined. Equation (6.2) can be written in...

How do I find the constants and the e vectors? I don't think I really understand what what I'm supposed to do represents...

Homework Statement I've done part A, and part D is easy. I'm stuck with part B. I have no idea what a "right hand side vector" is... Homework Equations The Attempt at a Solution Part A: All eigenvectors are valid. Eigenvalues are 1, 1/2 and 1/3.

Ahh that makes sense. Actually it makes little sense. Why the US isn't metric makes no sense at all.

The correct answer begins with Ay = 223.4835 lbf. Why is it lbf? Shouldn't it be lb?

I'm sorry nvn, I'm not sure what a double arrowhead vector is. I treated it as two equal forces in opposite directions each of magnitude 12.5 lb at 0.5ft from the vector...

I was trying to sum the moments around the origin. Thanks for the help, I will try your advice...

As I mentioned earlier I HAVE NO IDEA how to break the moments into components properly... I don't think I'm doing it right.

Ok so I did the problem and got all of the answers wrong... Still need help. Here are my equations and answers: Force equilibrium: Bx+Cx=0 Ay+By=0 Az+Cz=250 Moment Equilibrium: x-axis: Cz=By y-axis: Bx+3Cx+(12.5)*(3+2*2^-2)=2Az+(12.5)*(3-2*2^-2) z-axis...

Ok so So... x: Bx+Cx+0=0 y: Ay+By+0=0 z: Az+Cz-250=0 I'm not really sure how to break the moment that is given up into components... Do you have any tips as to which points I should sum my moments about? If I had my text this would be a lot easier... Unfortunately it was left in checked...

Here is the original picture before the FBD: The bent rod is supported at A, B and C by smooth bearings. Compute the x, y, z components of reaction at the bearings if the rod is subjected to a 250-lb vertical force and a 25-lb•ft couple as shown. The journal bearings are in proper alignment and...

I'm sure. I was given it and all the moments in the book are given that way. That's the only information I was given as well...

It's just to show the direction of the moment. The counterclockwise arrow and the arrow going through it are the same vector.

Which is the third unlabeled vector?