Recent content by Tino

So just get the numbers for this formula and only to get the LOAD ! What does the question mean by is the design safe !?? i don't know what to caluclate for that or wrtie about?? how do i caulate the maximum allowable load when the strut is restrainted is there a different formula ...

Revision on Past Exam Paper ! Hey there, i am stuck on this question in my past exam paper, and i have tried many ways of doing it but just simply not getting any where ! So please would u mind helping me out a little here !?? A rectangular cross section hollow steel tube (outer diameter 50...

Thanks a bunch Well here is me email address : bobbick2002@yahoo.co.uk Thanks a lot man i owe u one ! I think i have 1.0 GB of space so

hmm Thanks But u know what my maths teacher said the exam is going to be hard and we have to apply the rules of maths into engineering problems so how can i study for it ? lol i really don't know I only have one chance to succeed in the exam to get distinction so lol Good luck yo...

Thanks ! Thanks for replying and the questions. I will try and do it now and post the answers to see if i have got it right thanks ! It does look alittle complicated lol but i will have a go ! I am only studying National diploma yr 2 lol ! Thanks

Give Me A Question To Do Please ! Hi there I have got a maths exam tomorrow, and i have to try and get a distinction grade to get into university, so would anyone give me some questions to do on the listed critera below: The questions tomorrow are going to be quite hard, and is not just...

done it ! ok here is the equation i used Q = XL/R = XC/R Q x R = XL 50 x 75 = 3750 ohms Q x R = XC 50 x 75 = 3750 ohms then just use XL = 2pie FL and XC = 1 / 2pie FC transpose that ! L = 2pie F / XL C = 1 / 2pie F XC But one more question...

I find this question very hard and i could not work out the answers, i have looked on the internet for forumals but they don't seem to work ?? Anyone got any methods to work through the question ? I found a website that is about RLC series circuits but looking into it, it really confuses me...

I think i have cracked it ! 1. voltage gain/loss = 20log V1/V2 = 20log (0.35/7) = - 26dB And the overall gain is 12dB - 26dB + 31dB = 17dB 2. The audience would hear around 50Hz - 14kHz. I don't know if my answers are corrected, if it isn't can u please corrected me . :approve...

I need help with the two questions below please because i just don't understand it !1 Questions 1. A signal processing system consists of a preamplifier, an amplifier and a filter connected in series. At a given frequency the preamplifier and the amplifier have gains of 12 dB and 31 dB...

Thanks I get you now thanks very much !

Confused again ! Yesterday & Today in the post the answer was : \frac{2}{9} sin(3x) - \frac{2}{3}x cos(3x) + C And now the answer is: -\frac {2}{3}xcos(3x) + \frac{2}{9}(sin(3x)dx Which one is right i know that they are the other way round from each other but which way can i put...

?? would it be : \frac{2}{9}sin(3x) + C or -\frac{2}{9}sin(3x) + C

Another silly question This is back to the integration by parts question : \int (2x Sin 3x) dx when i put all the u, v, dx etc into the equation below: \int udv = uv - \int vdu It looks something like this right: \int2x\sin{(3x)}dx = (2x)(-\frac{1}{3} cos{(3x)}+c - \int...

Thanks Thanks for your help anyways !