Recent content by Tissue

the torque produced by the action of the spring with the kΔx should be LkΔx. And Δx should be equal to Lsin(the angle), at the same time with small anglur displacement, sin(the angle)=the angle. With the torque equal Ia, w=sqrt(kL^2/I)?

OK . So the horizontal position is the equilibrium, which the spring already compressed to a certain extend (change in l, and l is the length of the unstretched spring). And the force should be equal to mg to balance the weight of the rod. When the rod is oscillating, moving up a certain...

How I derive that it is a pendulum, is it simply because the spring will bring the rod to the equilibrium when the spring is compressed or stretched? And why it is not the case of physical pendulum?

Homework Statement Question 8 Homework Equations E=(kx^2)/2 E=(Iw^2)/2 I=(ml^2)/3 The Attempt at a Solution I don't know how to start to solve the problem, because I don't really know which part should I refer to. First I use the energy. So the energy stored in the spring will converted to...

Actually I have difficulties in figuring out what is meant by the force constant k. And what is shown by the equation above? Sorry for no pretty understand what is resonance completely.

now I get the frequency of the system and A, what about the value of k( the force constant of the system)?

When deciding the amplitude, the term in cosine can be treated as the maximum which is one? If this is correct, then and A/A0 =1/e T is the period of the bridge system should be 1s (not sure)

So for the damping constant, the only way I can think of is the equation of damped oscillation which is x=Ae-bt/2mcos(wt+fri) am I correct?

Sorry, can anyone help me?

Homework Statement On June 10, 2000, the Millennium Bridge, a new footbridge over the River Thames in London, England, was opened to the public. However, after only two days, it had to be closed to traffic for safety reasons. On the opening day, in fact, so many people were crossing it at the...

Thank you very much. Get the answer finally. May I ask how to quote the formula for the angular momentum in a more systematic way like you?

OK Thanks a lot. As angular momentum is conserved. mv(for apogee)*7.53*106=mv(for perigee)*6.81*106 Then v(for apogee)=0.90428v(for perigee) M is equal to the mass of earth As energy is also conserved. mv(for perigee)/2-GMm/7.53*106=mv(for apogee)/2-GMm/6.81*106

The angular momentum is conserved as the gravitational pull by the Earth is always perpendicular to the motion, no matter where is the position of the Sputnik I . And L=mvr

Homework Statement Sputnik I was launched into orbit around Earth in 1957. It had a perigee (the closest approach to Earth, measured from Earth's center) of 6.81 × 106 m and an apogee (the furthest point from Earth's center) of 7.53 × 106 m. What was its speed when it was at its perigee? The...

angular velocity of the gate is 1.71rad/s