Recent content by TissueCulture

Yes I was about to add that in fact, the force being already known, it would rather go like: T1 = m1*g → M1 = T1/g Which gives the mass! Thanks a lot again for your help!

Aaaah I think I get why I thought it divides the force by 2. I somehow subconsciously considered this system as a combined pulley system, with each pulley being fixed of course but the ''knot'' acting as a movable pulley, which is not the case! I now assume that it is clearly T1 = m1, since ...

What I mean to say is, I thought that a pulley divided by a factor of 2 the force necessary to lift it. I'm not sure exactly where I have read that, I cannot find it in my notes...Maybe I am mistaken! I sure know now that T1 is 627,8N but my brain seems to tell me there is more to it than simply...

Hi again! Here is what I found so far, if correct I only have one other question! ∑F = T1 + T2 + T3 (with vector arrows) ∑Fx = -T1cos45 + T3cos37 = 0 ∑Fy = T1sin45 - T2 + T3sin37 = 0 1) -T1cos45 + T3cos37 = 0 T1 = (T3cos37)/cos45 = 1,129T3 2) T3(1,129*sin45 + sin37) - T2 = 0...

Thank you very much! in fact, both angles had to be measured in real life but I thought I had to consider the angle in relation to the positive X axis (I don't know if this is clear), so I ended up with 135 degrees. However, I suppose it is more logical or easier to go with 45 degrees now that...

One thing I can't get my head around is if I must substract the masses with both ∑Fx and ∑Fy ∑Fx = -T1*cos135 - m1g + T3*cos37 + m3g = 0 ∑Fy = (T1*sin135 + m1g) + (T3*sin37 + m3g) - T2 - 778.6 N = 0 Are these valid to start the problem? I have a hard time understanding how to ''translate'' the...

So if I understand correctly, you mean that I should consider that T1,T2 and T3 vectors are pulling away from the red knot instead of towards it? Wouldn't that make them go in the same direction as the m1g, m2g and m3g vectors? Or is it an error on my part to consider the masses of the objects...

Homework Statement System is in equilibrium. 1 mass known: 79.4 kg (or 778.6 N) and 2 other unknown. Other masses unaccounted for. Everything friction-less. The Tensions are unknown also. Homework Equations ∑F = 0 ∑Fx = -T1*cos135 + -T3*cos37 = 0 ∑Fy = (-T1*sin135 - m1g) + (-T3*sin37 -...