Recent content by tjhollis1

Wait, hold on... It works only if trained initial guesses. That is the main problem. It looks like there are tons of solutions to each given. I am traveling tomorrow and I am putting this down for now. Please don't look further into this until I can sort out why the behavior of the convergence...

Ok, I've solved it but ohh boy is it a headache... I didn't want to, but I've solved it using multivariate Newton-Raphson method. I decided to pick two equations that included the following variables: ## T_1## or ##T_2## depending on which is higher as this is a limiting factor. As it has been...

Give me some time before I dig through this, but I think you are spot on. I am using C# and utilizing Newton-Raphson solver method so I think I can reduce this down to a single equation with a single variable. Albeit, there may be two solutions but I think I can come up with an initial value...

Thanks for your reply. I have thought about this over the past few days and I feel this conversation has gone off topic. I want an equation that will dictate the sag given total tension, ##T_{max}## at each end, ##d##, the space distance and, ##y_A## and ##y_B##, the height at each pole. I see...

Ok, I have thought about this more.. The equation I found above, assumes the center position to be ##x = x_A + x_B##. Substituting for ##x_B = x - x_A##, the result is below. $$0 = y_0^2 \cdot [\cosh^2(\frac {x - x_A} {y_0}) -2 \cdot \cosh(\frac {x - x_A} {y_0}) \cosh(\frac {x_A} {y_0}) +...

Thanks for your reply, Geometrically, I agree with ## d^2 = (y_B - y_A)^2 + (x_A + x_B)^2##. I have substituted in the equations for the ##y_A## and ##y_B## and got the result below. $$0 = y_0^2 \cdot [\cosh^2(\frac {x_B} {y_0}) -2 \cdot \cosh(\frac {x_B} {y_0}) \cosh(\frac {x_A} {y_0}) +...

Hi all, I am no structural engineer and I have toiled extensively over this for far too long and at this point I am wondering if this problem has a solution with the given variables... It is my understanding that the standard equation for a Catenary is: ##y = a \cdot cosh(\frac {x}{a})##...