Recent content by tk95

You were right, it's because of the units. The radius was measured in centimeters but the standard units for g are in meters, so the real answer is 3.26 grams/(rad2/s2) * 9.80 m/s2 * 100 cm / 1m / 16.00cm = 199.7 grams. Does that sound right?

I really don't think anybody is going to write your report for you.

M = m * r / g * ω2 becomes y = m * r / g * x so m * r / g = 3.26 Solving for m, you get m = 3.26 * g / r. This is the same as in my previous reply, 1.997 or about 2. Am I still missing something here?

Ok, so we rewrite as: m = M * g / (r * ω2) or we can also write as m = (M / ω2) * (g / r) since as I identified previously, the coefficient 3.26 represents M / ω2. Plugging this in we get 3.26 * 9.8 / 16, which gives a value of 2.0 g. The hanging mass was definitely greater than 2 grams.

This is from the lab: You start with the magnitude of centripital force acting on the object: F net = m * v2 /r Tangential speed of an object in uniform motion: v = 2 pi r / T (T is period of revolution) Rotational speed: ω = 2 pi / T so v = 2 * ω * r Plug this back into initial equation, F...

Yes, it's (a). I understand that the coefficient (3.26) represents the slope. The slope represents m / ω^2 (rise over run or y/x), which doesn't seem useful since this term is not in the other formula, m * (r/g) * ω2

So this question is from a physics lab. The apparatus for the experiment was made upon a device that measures angular speed over time. On top of this is a rail to which different items can be attached. Directly in the center of the rail is a device which has a pulley with a string to attached...