Hello, guys!
Yesterday I saw my reflection in a mirror and noticed that my teeth had two images on the mirror, and the rest of my face did not. I tried in different mirrors, and the result was the same. At first, I thought it could be the effect of two surfaces of the mirror, and in that case...
Ohh, I got it!
(1) Initial capacitance: 0A/d
When we introduce the conductor, each of the "two capacitors" will have capacitance = 3\epsilon0A/d. Since I can assume the "two capacitors" are arranged in series, Final capacitance = Capacitance/2. So, final capacitance will be...
Homework Statement
Hello, guys! Here I am again asking for your help...This is question number 2 from http://www.studyjapan.go.jp/en/toj/pdf/007.pdf"
2) Consider the circuit shown in Fig. 5, consisting of a battery of voltage E, a switch S, and a parallel-plate capacitor with capacitance C...
Hello again, guys!
I did some research, and I found one exercise very similar to this one on Halliday's book(4th edition, vol. 2, chapter 14).
Turns out that, when you have two springs that are exactly the same on a body on simple harmonic motion, the formula for the frequency is...
Yeah, I got that, thanks a lot for the help so far!
But I was thinking...If the springs had different constants, how could this problem be solved? I guess I can't use simple harmonic motion in this case, right?
Thanks again ^^
The time period will be T=2pi(m/k)^1/2.
So, T=2pi(0.5/12.25)^1/2, T=1.2 s aproximatedly.
The time for the ball to go up will be T/2, which is 0.6 s.
But the official answer is 0.45 s. What have I done wrong?
Thanks a lot.
Homework Statement
Hello, guys! This problem is from exercise D, Q4 http://www.studyjapan.go.jp/pdf/questions/10/ga-phy.pdf"
Consider two springs of negligible mass that have the same natural length (50 cm) and same spring constant. As shown in Figure 1 (view the link), the two srpings are...