Recent content by Tntgsh

Hello, guys! Yesterday I saw my reflection in a mirror and noticed that my teeth had two images on the mirror, and the rest of my face did not. I tried in different mirrors, and the result was the same. At first, I thought it could be the effect of two surfaces of the mirror, and in that case...

Ohh, I got it! (1) Initial capacitance: 0A/d When we introduce the conductor, each of the "two capacitors" will have capacitance = 3\epsilon0A/d. Since I can assume the "two capacitors" are arranged in series, Final capacitance = Capacitance/2. So, final capacitance will be...

Homework Statement Hello, guys! Here I am again asking for your help...This is question number 2 from http://www.studyjapan.go.jp/en/toj/pdf/007.pdf" 2) Consider the circuit shown in Fig. 5, consisting of a battery of voltage E, a switch S, and a parallel-plate capacitor with capacitance C...

Hello again, guys! I did some research, and I found one exercise very similar to this one on Halliday's book(4th edition, vol. 2, chapter 14). Turns out that, when you have two springs that are exactly the same on a body on simple harmonic motion, the formula for the frequency is...

Yeah, I got that, thanks a lot for the help so far! But I was thinking...If the springs had different constants, how could this problem be solved? I guess I can't use simple harmonic motion in this case, right? Thanks again ^^

If we assume the springs are arranged in parallel, we find 0,45 as an answer. K = 12.25 + 12.25 = 24.5 T=2pi(0.5/24.5)^1/2=0.9 0.9/2=0.45

The fact that the ball is attached to two springs has no influence on the time period formula?

The time period will be T=2pi(m/k)^1/2. So, T=2pi(0.5/12.25)^1/2, T=1.2 s aproximatedly. The time for the ball to go up will be T/2, which is 0.6 s. But the official answer is 0.45 s. What have I done wrong? Thanks a lot.

Homework Statement Hello, guys! This problem is from exercise D, Q4 http://www.studyjapan.go.jp/pdf/questions/10/ga-phy.pdf" Consider two springs of negligible mass that have the same natural length (50 cm) and same spring constant. As shown in Figure 1 (view the link), the two srpings are...