Recent content by toastermm

Thanks, that helps me understand it a bit better. So, continuing that thought, if \bar{X} = \frac{1}{a} , then that implies \bar{U} = a -1,\textrm{ and } \bar{W} = 0. This means that \bar{Y} = \bar{Z}. So a-1 = 2 \bar{Y}. Hence \bar{Y} = \bar{Z} = \frac{a-1}{2} . But I'm still...

Continuing to the Jacobian anyways, we arrive at J = \left[ \begin{array}{ccc} -1 - (\bar{Y} + \bar{Z}) & -\bar{X} & -\bar{X} \\ a\bar{Y} & a\bar{X}-1 & 0 \\ a\bar{Z} & 0 & a\bar{X}-1 \end{array} \right]. Plugging in what we know, J = \left[ \begin{array}{ccc} -a &...

I'm running into a problem. This is mainly for reading over the summer and I'm working on getting through a dynamical systems book on my own. I've come across a system that I'm not too sure on the procedure. Consider the following system of differential equations: \frac{dX}{dt} = 1 - X -...