Recent content by TomBanks

The worst case press fit I have is a thin walled cylinder, where the outer ring has an inside diameter of 108.5mm and a wall thickness of 2,25mm (Outisde dimaeter of 113mm). The pressure I know from step 1 (first post) to be 8.475 N/mm^2. So the Hoop stress = Pressure x Inside Radius / wall...

1mm is completely impractical, agreed, but I want to be able to explain why mathmatically. I will try and account for shock loading.

Thanks again for the reply. I will take the segment approach to calculating the bending moment's effects upon the press fit. Is there a way for me, mathmatically, to determine how much of the stress I appropriate to the torque transmission and how much to the bending moment?

Nidum, thank you. Not only is this a thorough reply but a speedy one, too. So I was on the right lines then? The equation I used in Part 3 is the same as 'Break away torque = interface shear stress * circumference * shaft radius * length of engagement' I was just shocked that it was giving me...

I think the first equation covers this? It's requires outside and internal diameters for the two components that make up the press fit.

Hello everyone. The physics forum is a great online community, and I used to spend a lot of time browsing the philosophy pages. But now I've had to register and post, because I've got a very specific problem with regards mechanical engineering. My problem is relating to torque transmission...