Recent content by tomclaessens

Thanks for everyone's help. It just needed someone to explain it to me, which my friend (a past A-Level physics student) kindly did. tomclaessens

For question number 1, I have attempted a solution again. Please could someone tell me whether this is correct or not: 3kg x 40cm/s = 1.2kgm/s therefore the total momentum after the collision is also 1.2kgm/s to calculate the speed, I divided 1.2kgm/s by 2kg, which gave me 0.6m/s or 60cm/s...

Thank you, but how can I find the momentum after the collision if I am not given the velocity? (For example, in question 1: it is the velocity I need to calculate (as well as the loss of kinetic energy))

I didn't know, but I found this on this internet: 'm1 u1 + m2 u2 = (m1 + m2) v' Is this correct and if so, what does it mean please?

I know they involve the convservation of momentum - that the initial momentum has to be the same as the momentum after the collision, but I don't understand how to use that to work it out? Believe me, I have given it a shot...

Homework Statement I am a GCSE Physics student, and my teacher recently set us a homework sheet in which he said contained questions 'exceeding A-Level standard'. He told us to get as far as we could. So, I have completed 12 of 18 questions, but I am very confused about the last 6: 1) A...