I believe I understand why we chose that equation to solve this. Could I say that if each person choosing a car is random and equal that the probability of person n1 selecting car c1 is the same as them selecting c2, c3,...,cx? Meaning in the binomial formula we can say that p = 1/cx where cx...
Quick question for you all...
If I had X number of train cars and I wanted to know the probability of having Y or more people in a car when I have N total of people. How would I go about solving this?
Thanks!