Recent content by tracey163

Ah thanks, yeah your right, I've got it :) it all makes perfect sense now :) y = 5/3.e^(2 + ix - (1 - 2ix)) =5/3.e^(1 + 3ix) dy/dx = 5ie^(1 + 3ix) :D thanks!

This is the way I tried to do it: (Quotient rule) dy/dx = ((5ie^(2 + ix))(3e^(1-2x)) - (-6ie^(1 - 2ix))(5e^(2 + ix))) / ((3e^(1 - 2ix))^2) = (15ie^(3 - ix) + 30ie^(3 - ix)) / (9(e^(1 - 2ix))^2) = (45ie^(3 - ix)) / (9(e^91 - 2ix)^2) = (5ie^(3 - ix)) / ((e^(1 -...

Could someone please help me with the method and steps to this question: Find dy/dx for the following: y = (5e^(2+ix))/(3e^(1-2ix))