Recent content by tracie

After the switch is closed, I can figure out how much current is flowing with I=V/Req. To find the potential at b, I thought it would just be I*R1, but that isn't right. The 6uF capacitor is discharging through 'b' now too, right? Wouldn't that effect my potential at 'b'? I know that the...

So the voltage drop between 'a' and 'b' would be 16V with b at the higher potential. Am I on the right track for part c and d of the question?

Homework Statement (a) What is the potential of point a with respect to point b in Fig. 26.61 (V = 16.0 V, R1 = 7.00 , R2 = 4.00 ) when switch S is open? (b) Which point, a or b, is at the higher potential? (c) What is the final potential of point b with respect to ground when switch S...

Thank you for correcting my typo. I guess I can relate C23 to C1 by initial charge on C1= q1 + q23 (since charge is conserved) Since I calculated initial charge on C1 and I can calculate q23 from q23=C23*V, then I can get q1. Since q2=q3, q23/2 = q2 = q3. I then can say V2= q2/C2 and...

I know that capacitors in series q=q1+q2, V=V1+V2, and C=q/V. After the switch is flipped, can I strictly treat C1 as a emf source? I guess I don't understand how to relate the simple series capacitor problem to the charge on C1 as well as the potential difference on C1. I assumed that (since...

Homework Statement Initially, a 120V emf is connected to C1 by a switch. When the switch is flipped C1 is connected to C2 and C3 in series. What are the charge and potential difference across each capacitor? C1 = 15 uF C2 = 16 uF C3 = 30 uFHomework Equations C= q/V 1/Ceq = 1/C1 + 1/C2 + ... +...