The tractor in its old agri set up at 99HP/75kW provided for a max torque of 360Nm. I assume that is provided at the 2200 RPM point and nothing has changed.
Does the following read correctly...?
Now substituting into the 'jack action' text - diesel the train puts out 75 kW @ 2400 rpm when...
I do not know the gear ratios of the tractor. Only that it has 4 gears (1st, 2nd, third and forth) with a high, medium and low range. So lying between the input shaft and the road surface there is in existence (a) a standard gear box, (b) a high, mid and low range box and the (c) differential...
Because this train combination has a max operating speed of 25km/hr on city streets I made no allowance for aerodynamic drag in the calculations. Again I read somewhere on the net that drag does not come into effect until higher speeds are involved. Might that be an incorrect assumption.
They may be a mess but I'm capable of further adding to a mess as I'm not really a Newton head. After the Environmental Summit in Scotland I got to thinking about converting the loco engine (diesel burner) to electric by removing the engine and installing an electric motor. Physically it seem...
For clarity the loco weight = approx 3500kg's. The coaches when loaded are = 3500kg's each. So the total kg's of the combination when loaded is 10.500kg's.
I worked out the RR + GR + AF for the loco and found it to be 9500 N and then applied it to the 3 vehicles that make up the combination...
Thanks jack actio, I will change the TTE in the second equation to reflect the vehicle (GVW) weight.
The torque requirements of the combination equates to 10,792 N.m at the road surface as the image outlines. This includes for an operational speed of 25km when fully loaded and a 5 degree slope...