Recent content by tranceical

Thanks ever so much guys I’ve learned loads! Much appreciated :).

Thanks a lot everyone for your replies. I really appreciate you taking the time out to enlighten me! The analogies have been a great read. A way I can explain how I have thought about it up to now is using the water pipe analogy for electricity. The higher the restriction or resistance in the...

Hi all, Sorry in advance if my questions are stupid and the answers are obvious. I can see from P=VI why a high power appliance requires more current to function. However looking at ohms law and I=V/R it’s telling me that greater resistance will lead to less current. I've always figured that...

Thanks a lot for help with this problem, it's much appreciated.

Heres my working (sorry its rough) Many thanks

I found a = 5 and omega = √2000-a^2 = 44.44 Then inputting step input, my partial fractions were: A/s +(Bs+C)/(s+5)^2+(44.44^2) The result: [-78.2/s + (78.2)s+782] / (s+5)^2 + 1975 Doesn't seem correct to me...

"Will the roots be real or complex?" complex... so in this scenario I should multiply out the denominator of the damped sine function to s^2+2as+a^2+omega^2...find my a and omega values, then partial fraction (remembering to add in the b/s from earlier) to form the damped sine and cosine...

After multiplying through by LRC it leaves me (1/LC)/[s^2 + (s(1/RC)) + 1/LC] Which leaves just the ω term 1/LC that i need to square. So i can write (√1/LC)^2 ? Then on to the partial fractions... I'm still keen to learn how this problem is solved it's just a shame I've needed so much...

Neither do i, there was no mathematical foresight...I have just been multiplying through by all sorts and seeing what it resulted in. I was trying not simplify too much because then i would have more terms to play with. Oh i don't know :blushing:

Would negative squared and what I've done be a valid match for the form you've suggested? :blushing: If not i will keep trying. Apologies for my poor algebra. Thankyou for your continued help and patience.

Thanks Gneill. Attached is my attempt at the algebra to get the expression into the g(s) form. I'm wondering if you can tell if if I'm close or on the right track? If the Tau term was somehow made to be 1/Tau rather than 2(tau), the ei(s) extracted, making the remaining numerator A then it...

Please could you explain what tau in the denominator represents/means? In my notes the inverse transform examples haven't ever got too complicated so I'm hoping it won't be a damped sine and damped cosine!

Thanks a lot for your help gneill, i'll follow your steps and get back to you.

Absolutely, i have a step input of 0.01v and my other values are R=100ohms L=0.5henrys and C = 0.001 farads. I am trying to understand this function $$G(s) = A \cdot \frac{1}{s^2 + \frac{1}{\tau}s + \omega_o^2}$$ It looks similar to functions from the table I'm working from (I've attached...

Hi Guys, I have an expression that i am struggling to manipulate into a laplace transform. This expression should fit one or a combination of the common transform pairs. I believe the transform the expression should be fitting is either a unit step 1/s a unit ramp 1/s^2 an exponential 1/s+a...