I think I figured it out. Ft at top = 0, gives speed of 1.4 m/s, using conservation of energy gets speed at bottom then use conservation of energy again to figure out height to drop bob from with 0 velocity. Then do some trig, yay! Anyway, I came up with an 80.5 degree angle. I can post...
I am working on solving the problem with speed, but my examples from book have mass in the bob given for kinematics, still looking for energy examples. This type of problem kicks me good.
A pendulum of length 0.6m swings so that at the bottom of its swing, it contacts a peg located 0.4m from the pivot point (0.2m from the CG). At what angle from vertical must the bob be released so that it will just make a revolution around the peg?
F = Mg = M*V^2/r
Mg (l-l cos x) = 1/2...