Okay, so when I go from there
y=c1*e^(-9/4 *t) + c2
y'=(-9/4)*e^(-9/4 *t)*c1 + c2??
Which leads me to
1=c1+c2
0=(-9/4)c1+c2
for y(0)=1 y'(0)=0
c1=(1-c2)
0=(-9/4)(1-c2) + c2
9/4=(13/4)*c2
c2=9/13
c1=4/13
but this isn't correct according to webwork, so what is the mistake? is...
Homework Statement
64y''+144y'=0
y1(0)=1 y'1(0)=0
and
y2(0)=0 and y'2(0)=1
Homework Equations
y1=c1*e^(r1*t) + c2*e^(r2*t)The Attempt at a Solution
I start by finding the characteristic equation:
64r^2+144r=0
r1=-9/4 and r2=0
y1=c1e(r1*t) + c2e(r2*t)
so I get
y1=c1e^(-9/4 *t) + c2e^(0*t)...